Answer:
A frictional force of 10N on the opposite direction can be used to balance the given force.
Explanation:
The net force is the sum of all forces acting on the object in different directions (x,y):
[tex]\sum F_{r} = ma[/tex] (1)
Where [tex]\sum F_{r}[/tex] represents the net force, m is the mass and a is the acceleration.
[tex]F_{x} + F{y} = ma[/tex] (2)
[tex]F_{x}[/tex] is the sum of the forces that are in the x direction, for this particular case [tex]F_{x}[/tex] has to be equal to zero to be balanced.
[tex]F_{x} = 10N - 10N [/tex]
[tex]F_{x} = 0[/tex]
So a force with the same magnitude but opposite direction is needed (-x).
Hence, a frictional force of 10N in the opposite direction can be used to balance the given force.
