Use the information below for Questions 5 - 11. Let X denote the number of telephone lines in use at an online business. Suppose there are 6 lines and p(0) = .1, p(1) = .15, p(2) = .2, p(3) = .25, p(4) = .2, p(5) = .06, and p(6) = .04. First, construct the probability distribution table and derive the cumulative distribution function and use both the answer the following questions. Question 8: Probability that between 2 and 5 lines, inclusive, are NOT in use.

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Answer:

Step-by-step explanation:

Given that  X denote the number of telephone lines in use at an online business.

The variable x can take values from 0 to 6 and the probability can be tabulated as follows:  Cumulative probability is the Prob =P(X<=x)

   

We want prob that between 2 and 5 lines, inclusive not in use

This is equivalent to

1-[tex]P(2\leq x\leq 5)[/tex]

=[tex]1-F(5)+F(2)\\=1-0.96+0.45\\=0.49[/tex]

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