Answer:
d = 0.391 m
Explanation:
given,
mass of sled = 18 kg
inclined at an angle of = 28°
kinetic friction between the sled and inclined = 0.25
using energy equation
[tex]\dfrac{1}{2}mv^2- Fd - mgh = 0[/tex]
[tex]\dfrac{1}{2}mv^2- (\mu mg cos\theta )d - mgdsin\theta = 0[/tex]
[tex]\dfrac{1}{2}mv^2 = (\mu mg cos\theta )d + mgdsin\theta[/tex]
[tex]\dfrac{1}{2}mv^2 = d mg (\mu cos\theta+sin\theta)[/tex]
[tex]d = \dfrac{v^2}{2g (\mu cos\theta+sin\theta)}[/tex]
[tex]d = \dfrac{2.3^2}{2\times 9.8 (0.25\times cos28^0+sin28^0)}[/tex]
d = 0.391 m
hence, the distance traveled by the sled is equal to 0.391 m
