Answer:
1.65×10⁻⁶ N
Explanation:
m = Mass of ant = [tex]3\times 10^{-6}\ kg[/tex]
r = Radius = 50 m
t = Time taken to complete on rotation = 60 seconds
Angular velocity
[tex]\omega=\frac{2\pi}{t}\\\Rightarrow \omega=\frac{2\pi}{60}[/tex]
Centripetal acceleration is force that is acting outward
[tex]F_c=m\omega^2r\\\Rightarrow F_c=3\times 10^{-6}\times \left(\frac{2\pi}{60}\right)^2\times 50\\\Rightarrow F_c=1.65\times 10^{-6}\ N[/tex]
The magnitude of the upward force felt by the ant due to the second hand would be 1.65×10⁻⁶ N
