Answer:
25 N
Explanation:
We are given that three boxes rest side-by-side on a smooth, horizontal floor.
[tex]m_1=5 kg[/tex]
[tex]m_2= 3 kg[/tex]
[tex]m_3=2 kg[/tex]
Force applied on 5 kg box=50 N
We have to find the magnitude force exert on the 3 kg box by 5 kg box.
According to given question
[tex]50=(5+3+2)a[/tex]
[tex]a=\frac{50}{10}=5 m/s^2[/tex]
When 5 kg box exert force on 3 kg box then equal and opposite force exert on 5 kg box due to 3 kg box and 2 kg box.
Let F be the force exert by 5 kg box on 3 kg box and
[tex]50-F=5\cdot 5[/tex]
[tex]F=50-25=25 N[/tex]
Hence, the magnitude force exert on 3 kg box by 5 kg box=25 N
