Answer:
The speed of the ball just before it strikes the ground is 15.90 m/s.
Explanation:
Given that,
Height = 109 m
Distance = 75 m
We need to calculate the time
Using formula for horizontal projectile
[tex]t=\sqrt{\dfrac{2h}{g}}[/tex]
Where, h = height
Put the value into the formula
[tex]t=\sqrt{\dfrac{2\times109}{9.8}}[/tex]
[tex]t=4.716\ sec[/tex]
We need to calculate the speed of the ball just before it strikes the ground
Using formula of speed
[tex]v =\dfrac{d}{t}[/tex]
Where, v = speed
d = distance
t = time
Put the value into the formula
[tex]v=\dfrac{75}{4.716}[/tex]
[tex]v=15.90\ m/s[/tex]
Hence, The speed of the ball just before it strikes the ground is 15.90 m/s.
