Answer:
The energy E is 1603.008 J.
Explanation:
Given that,
Capacitor = 18.4 μF
Voltage = 13.2 kV
We need to calculate the energy
Using formula of energy
[tex]E=W=\int{Q}\ dV[/tex].....(I)
We know that,
[tex]Q=CV[/tex]
Put the value of Q in equation (I)
[tex]E=\int{CV}dV[/tex]
On integration
[tex]E=\dfrac{CV^2}{2}[/tex]
Put the value into the formula
[tex]E=\dfrac{18.4\times10^{-6}\times(13.2\times10^{3})^2}{2}[/tex]
[tex]E=1603.008\ J[/tex]
Hence, The energy E is 1603.008 J.
