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Performing Young's double slit experiment using a typical laser pointer with 650 nm wavelength pro duces the first-order maximum at an angle of 32 degrees. At what angle will the first-order maximum occur when repeating the experiment with a laser from a Blueray player, which has a wavelength of 405 nm?

Respuesta :

Answer:[tex]\theta =19.27^{\circ}[/tex]

Explanation:

Given

wavelength of source=650 nm

angle of bright fringe[tex]=32^{\circ}[/tex]

let d be the distance between slits

[tex]\sin \theta _{bright}=\frac{m\lambda }{d}[/tex]

[tex]\sin32=\frac{1\times 650}{d}[/tex]------1

For \lambda =405 nm

[tex]sin\theta =\frac{1\times 405}{d}[/tex]------2

Divide 1 & 2

[tex]\frac{sin32}{sin\theta }=\frac{650}{405}[/tex]

[tex]\theta =19.27^{\circ}[/tex]

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