Answer:
Final velocity will be 92.851 m/sec
Explanation:
We have given length of runway that is s = 400 m
Acceleration [tex]a=10.8m/sec^2[/tex]
As the airplane starts from rest so initial velocity u = 0 m/sec
Now according to third equation of motion [tex]v^2=u^2+2as[/tex]
[tex]v^2=0^2+2\times 10.8\times 400=8640[/tex]
v = 92.851m/sec
So final velocity will be 92.851 m/sec
