Answer:
0.139 rad
Explanation:
We use Snell's law [tex]n_1sin\theta_1=n_2sin\theta_2[/tex], where if [tex]n_1[/tex] is the refractive index of the medium containing the incident ray, [tex]\theta_1[/tex] would be the incident angle, and if [tex]n_2[/tex] is the refractive index of the medium containing the refracted ray, [tex]\theta_2[/tex] would be the refraction angle, which we want, so we do:
[tex]sin\theta_2=\frac{n_1}{n_2}sin\theta_1[/tex]
And finally:
[tex]\theta_2=arcsin(\frac{n_1}{n_2}sin\theta_1)[/tex]
We then insert our values:
[tex]\theta_2=arcsin(\frac{n_1}{n_2}sin\theta_1)=Arcsin(\frac{1}{3.325}sin(0.478rad))=arcsin(0.13834714686
)=0.139 rad[/tex]
