Answer:
v = 16.82 m/s
Explanation:
It is given that,
The altitude of a hang glider is increasing at a rate of 6.55 m/s, [tex]v_1=6.55\ m/s[/tex]
The shadow of the glider moves along the ground at a speed of 15.5 m/s, [tex]v_2=15.5\ m/s[/tex]
Here, the horizontal velocity is v₁ and the vertical velocity is v₂. Let v is the magnitude of glider's velocity. It can be calculated as :
[tex]v=\sqrt{v_1^2+v_2^2}[/tex]
[tex]v=\sqrt{6.55^2+15.5^2}[/tex]
v = 16.82 m/s
So, the magnitude of the glider's velocity is 16.82 m/s. Hence, this is the required solution.
