Answer:
Ball will take 1.9591 sec to reach the ground
Explanation:
We have given initial velocity of the ball u = 10 m/sec
Height from which ball is thrown h = 38.4 m
Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]
From second equation of motion we know that [tex]h=ut+\frac{1}{2}gt^2[/tex]
[tex]38.4=10t+4.9t^2[/tex]
[tex]4.9t^2+10t-38.4=0[/tex]
After solving equation for t
t= -4 sec and t = 1.9591 sec
As time can not be negative so time will be 1.9591 sec
