A 0.40-μF capacitor is connected to a 5.0-V battery. How much charge is on each plate of the capacitor? Express your answer using two significant figures.

Respuesta :

AMB000

Answer:

[tex]Q=2.0\times10^{-6}C[/tex]

Explanation:

The equation of charge on the capacitor given its capacitance and a voltage applied to it is Q=CV.

Our capacitance is expressed in microfarads, where micro stands for [tex]\times10^{-6}[/tex], so in S.I. we sill have:

[tex]Q=CV=(0.4\times10^{-6}F)(5V)=0.000002C=2.0\times10^{-6}C[/tex]

Where the results has been expresed with two significant figures.