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A van de Graaff generator has an aluminum sphere on top with a radius of 8.7 cm and carries a charge of -1.25 microcoulombs (μC). What is the potential, V, in volts, at the surface of the sphere? Enter your answer in exponential notation.

Respuesta :

Answer:

[tex]V = -1.29 \times 10^5 Volts[/tex]

Explanation:

Electric potential at the surface of the sphere is given as

[tex]V = \frac{KQ}{R}[/tex]

here we know that

[tex]k = 9 \times 10^9[/tex]

[tex]Q = -1.25 \mu C[/tex]

[tex]R = 8.7 cm[/tex]

now from above formula we will have

[tex]V = \frac{(9 \times 10^9)(-1.25 \times 10^{-6})}{0.087}[/tex]

[tex]V = -1.29 \times 10^5 Volts[/tex]

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