Answer:[tex]V_{avg}=53.60 km/h[/tex]
Explanation:
Given
In first interval velocity=80.9 km/h for 27.7 min
In second interval=117 km/h for 12 min
In third interval=40.2 km/h for 46.3 min
Also she spends 16.7 min while eating and buying gas
[tex]Distance =80.9\times \frac{27.7}{60}+117\times \frac{12}{60}+40.2\times \frac{46.3}{60}[/tex]
Distance=91.761 m
[tex]V_{avg}=\frac{Displacement}{total\ time}[/tex]
[tex]V_{avg}=\frac{91.761}{27.7+12+46.3+16.7}\times 60[/tex]
[tex]V_{avg}=53.60 km/h[/tex]
