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The force F = (-90, 40) N acts on a mass of 8 kg. At time t = 0 s, the mass is initially at rest. What is the magnitude of the force (in N)? What are the (x,y) components of the acceleration vector (in m/s^2)? What are the (x,y) components of the velocity vector (in m/s) after 1 seconds?

Respuesta :

Answer:

Explanation:

Given

Force=(-90,40 ) N

i.e. [tex]F_x=-90 N[/tex]

[tex]F_y=40 N[/tex]

mass of object=8 kg

to get x component of acceleration

[tex]a_x=\frac{-90}{8}=-11.25 m/s^2[/tex]

[tex]a_y=\frac{40}{40}=1 m/s^2[/tex]

Velocity after 1 sec

[tex]v_x=u_x+a_xt[/tex]

[tex]v_x=0-11.25\times 1=-11.25 m/s[/tex]

[tex]v_y=u_y+a_yt[/tex]

[tex]v_y=0+1\times 1=1 m/s[/tex]

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