A spring loaded gun shoots a 0.1 kg bullet vertically downward with an initial speed of 16 m/s. How far is the bullet from the muzzle 0.3 s after firing? A) 5.24m below the muzzle
B) 5.24m above the muzzle
C) 0.441m below the muzzle
D) 4.36 m below the muzzle

Respuesta :

Answer:

The distance of the bullet is 5.24 m below the muzzle.

(A) is correct option.

Explanation:

Given that,

Mass of bullet = 0.1 kg

Initial speed = 16 m/s

Time = 0.3 s

We need to calculate the distance

Using equation of motion

[tex]s=ut+\dfrac{1}{2}gt^2[/tex]

Where, u = initial speed

g = acceleration due to gravity

t = time

Put the value into the formula

[tex]s=16\times0.3+\dfrac{1}{2}\times9.8\times(0.3)^2[/tex]

[tex]s=5.24\ m[/tex]

Hence, The distance of the bullet is 5.24 m below the muzzle.

Answer:

(a) 5.24 m bellow the muzzle      

Explanation:

We have given that initial velocity of the bullet u = 16 m/sec

Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]

Time t = 0.3 sec

We have to find the height

According to second equation of motion

[tex]h=ut+\frac{1}{2}gt^2[/tex]

[tex]h=16\times 0.3+\frac{1}{2}\times 9.8\times 0.3^2=5.241m[/tex]

As the bullet is shoots downward so distance will be billow the muzzle

So option (a) will be correct option