Answer:
The answer to your question is: C₂ = 0.115 M
Explanation:
Data
C₂H₄O₂ = 50 ml concentration = ?
NaOH = 1 M; 5.75 ml
Formula
C₁V₁ = C₂V₂
C₂ = C₁V₁/V₂
C₂ = (1)(5.75) / 50
C₂ = 0.115 M
Explanation:
The given data is as follows.
[tex]M_{1}[/tex] = 1.00 M, [tex]V_{1}[/tex] = 50.0 ml
[tex]M_{2}[/tex] = ?, [tex]V_{2}[/tex] = 5.75 ml
Therefore, calculate the concentration (in M) of acetic acid as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]
[tex]1.00 M \times 50.0 ml = M_{2} \times 5.75 ml[/tex]
[tex]M_{2}[/tex] = [tex]\frac{1.00 M \timess 50.0 ml}{5.75 ml}[/tex]
= 8.69 M
Thus, we can conclude that the concentration (in M) of acetic acid present in the given vinegar is 8.69 M.
