Explanation:
It is given that,
1. Energy of neutron, [tex]E_1=0.01\ eV=0.01\times 1.6\times 10^{-19}\ J=1.6\times 10^{-21}\ J[/tex]
The energy of neutron is given by :
[tex]E_1=\dfrac{hc}{\lambda_1}[/tex]
[tex]\lambda_1=\dfrac{hc}{E_1}[/tex]
[tex]\lambda=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{1.6\times 10^{-21}}[/tex]
[tex]\lambda_1=1.24\times 10^{-4}\ m[/tex]
2. [tex]E_2=10\ MeV=10^7\ eV=1.6\times 10^{-19}\times 10^7=1.6\times 10^{-12}\ J[/tex]
The energy of neutron is given by :
[tex]E=\dfrac{hc}{\lambda}[/tex]
[tex]\lambda_2=\dfrac{hc}{E_2}[/tex]
[tex]\lambda_2=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{1.6\times 10^{-12}}[/tex]
[tex]\lambda_2=1.24\times 10^{-13}\ m[/tex]
Hence, this is the required solution.
