Answer:
Explanation:
Given
angle through which ball is launched[tex]=45^{\circ}[/tex]
Range of ball=50 m
Range of projectile is [tex]=\frac{u^2sin2\theta }{g}[/tex]
[tex]50=\frac{u^2sin90}{9.8}[/tex]
u=22.136 m/s
If ball is thrown straight upward
[tex]v^2-u^2=2as[/tex]
[tex]0-(22.136)^2=2(-9.8)s[/tex]
[tex]s=\frac{22.136^2}{2\times 9.8}[/tex]
s=25 m
(b)For Projectile time of flight is
[tex]t=\frac{2usin\theta }{g}[/tex]
[tex]t=\frac{2\times 22.136\times sin45}{9.8}[/tex]
t=3.19 s
