Explanation:
It is given that,
Electric field, [tex]E=4.99\times 10^6\ N/C[/tex]
The relation between the electric force and the electric field is given by :
[tex]F=qE[/tex]
Where
q is the charge
(a) Charge on the electron, [tex]q_e=-1.6\times 10^{-19}\ C[/tex]
Electrostatic force,
[tex]F=-1.6\times 10^{-19}\times 4.99\times 10^6[/tex]
[tex]F=-7.98\times 10^{-13}\ N[/tex]
(b) If an electron is missing, the net charge remains the same only sign changes.
So, force becomes, [tex]F=7.98\times 10^{-13}\ N[/tex]
Hence, this is the required solution.
