Answer:
Acceleration of the electron will be [tex]0.379\times 10^{16}m/sec^2[/tex]
Explanation:
We have given electric field [tex]E=2.16\times 10^4N/C[/tex]
Charge on electron [tex]q=1.6\times 10^4C[/tex]
So force in the electron [tex]F=qE=1.6\times 10^{-19}\times 2.16\times 10^{4}=3.456\times 10^{-15}N[/tex]
Mass of electron [tex]m=9.11\times 10^{-31}kg[/tex]
Now according to newton second law
F = ma, here m is mass and a is acceleration
So [tex]3.456\times 10^{-15}=9.11\times 10^{-31}a[/tex]
[tex]a=0.379\times 10^{16}m/sec^2[/tex]
So acceleration of the electron will be [tex]0.379\times 10^{16}m/sec^2[/tex]
