Answer:
k = 26319 N/m
Explanation:
given,
Period of bounce = 1.5 s
mass of the car = 1500 kg
four springs
to find the value of k
[tex]T = 2\pi \sqrt{\dfrac{m}{k}}[/tex]
[tex]1.5 = 2\pi \sqrt{\dfrac{1500}{k}}[/tex]
[tex]\dfrac{2.25}{4\pi^2}=\dfrac{1500}{k}[/tex]
[tex]k = \dfrac{4\pi^2 \times 1500}{2.25}[/tex]
k = 26319 N/m
Now the value of force constant is k = 26319 N/m