Alice buys some inexpensive bracelets and necklaces as party favors for her jewelry showing. She pays $8 for each necklace (N) and $7 for each bracelet (B). She spends less than $120. Which inequality models this situation?
A) 7B + 8N ≤ 120
B) 7B + 8N > 120
C) 7B + 8N ≥ 120
D) 7B + 8N < 120

The total amount of the bracelets and necklaces is less than $120, so if you add the price of each necklace ($8) and the price of each bracelet ($7), it will be <$120.

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JeanaShupp JeanaShupp · Answer 2 · 2019-10-22T04:57:39+02:00

Answer: D. [tex]7B + 8N < 120[/tex]

Step-by-step explanation:

Given : Alice buys some inexpensive bracelets and necklaces as party favors for her jewelry showing.

She pays $8 for each necklace (N) and $7 for each bracelet (B).

Then , the cost of N necklaces = $8N

Cost of B bracelets = $7B

Total money spent = Cost of N necklaces+ Cost of B bracelets

=$(8N+7B)

She spends less than $120.

i.e. $(8N+7B) < $120

Hence, the inequality models this situation :

[tex]7B + 8N < 120[/tex]

Alice buys some inexpensive bracelets and necklaces as party favors for her jewelry showing. She pays $8 for each necklace (N) and $7 for each bracelet (B). She spends less than $120. Which inequality models this situation? A) 7B + 8N ≤ 120 B) 7B + 8N > 120 C) 7B + 8N ≥ 120 D) 7B + 8N < 120

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Alice buys some inexpensive bracelets and necklaces as party favors for her jewelry showing. She pays $8 for each necklace (N) and $7 for each bracelet (B). She spends less than $120. Which inequality models this situation?
A) 7B + 8N ≤ 120
B) 7B + 8N > 120
C) 7B + 8N ≥ 120
D) 7B + 8N < 120