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A person of mass 68.1 kg escapes from a burning building by jumping from a window situated 27.4 m above a catching net. The acceleration of gravity is 9.8 m/s 2 . If air resistance exerts a force of 105.4 N on him as he falls, determine his speed just before he hits the net. Answer in units of m/s

Respuesta :

Answer:21.27 m/s

Explanation:

Given

Mass of person(m)=68.1 kg

height of window=27.4 m

Air resistance =105.4 N

air resistance deceleration[tex]=\frac{105.4}{68.1}=1.54 m/s^2[/tex]

let V be the Velocity of person before hitting

[tex]v^2-u^2=2as[/tex]

[tex]v^2-0=2(9.8-1.54)27.4[/tex]

[tex]v=\sqrt{452.648}=21.27 m/s[/tex]

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