Answer:
Frequency of homozygous dominant genotype BB (p2) = 0.3025
Frequency of heterozygous dominant genotype Bb (2pq) = 0.495
Frequency of homozygous recessive genotype (white) in the population = 0.2
Explanation:
20% of the bears are white.
20% of 1300 = 260
Frequency of homozygous recessive genotype (white) in the population (q2)= 260 /1300= 0.2
Frequency of recessive allele W (q) = square root of 0.2 = 0.45
Since p+q =1
Frequency of dominant allele B (p)= 1-0.45 = 0.55
Frequency of homozygous dominant genotype BB (p2) = 0.55 x 0.55 = 0.3025
Frequency of heterozygous dominant genotype Bb (2pq) = 2 x 0.55 x 0.45 = 0.495