Answer:
The ratio of asteroid-A’s acceleration to asteroid-B’s acceleration is 19:340.
Explanation:
Mass of asteroid-A = m =[tex]1.70\times 10^{20} kg[/tex]
Mass of asteroid-B = m' =[tex] 9.50\times 10^{18} kg[/tex]
As we know , Force = mass × Acceleration
Force on asteroid-A
[tex]F = m\times a[/tex]
where , a is the acceleration with which asteroid-A is moving
Force on asteroid-B
[tex]F' = m'\times a'[/tex]
where , a' is the acceleration with which asteroid-B is moving
Same force is exerted on the both the asteroids say F.
F = F'
[tex]m\times a=m'\times a'[/tex]
[tex]\frac{a}{a'}=\frac{9.50\times 10^{18} kg}{1.70\times 10^{20} kg}=\frac{19}{340}[/tex]
The ratio of asteroid-A’s acceleration to asteroid-B’s acceleration is 19:340.
