Answer:
[tex]\large\boxed{y=\dfrac{2}{3}x+1}[/tex]
Step-by-step explanation:
The slope-intercept form of an equation of a line:
[tex]y=mx+b[/tex]
m - slope
b - y-intercept → (0, b)
The fromual of a slope:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
(x₁, y₁), (x₂, y₂) - points on a line
We have the points from the graph:
(0, 1) → b = 1 and (3, 3).
Calculate the slope:
[tex]m=\dfrac{3-1}{3-0}=\dfrac{2}{3}[/tex]
Finally we have the equation of a line:
[tex]y=\dfrac{2}{3}x+1[/tex]
