A ship is moving at a speed of 25 km/h parallel to a straight shoreline. The ship is 9 km from shore and it passes a lighthouse at noon. (a) Express the distance s between the lighthouse and the ship as a function of d, the distance the ship has traveled since noon. s = f(d) = (b) Express d as a function of t, the time elapsed since noon. d = g(t) = (c) Find f ∘ g. (f ∘ g)(t) =

Respuesta :

Explanation:

It is given that,

Speed of the ship, v = 25 km/h

Distance between the ship and the shore is 9 km

Let s is the distance between the lighthouse and the ship and d is the distance traveled by the ship since noon.

(a) Using Pythagoras theorem in the attached diagram as :

[tex]s^2=9^2+d^2[/tex]

[tex]s^2=81+d^2[/tex]

[tex]s=\sqrt{81+d^2}[/tex]

or [tex]f(d)=\sqrt{81+d^2}[/tex]

(b) Let g(t) is the function at t = 0 and at 12 pm.

[tex]f(g)=fog[/tex]

Since, distance, d = 25t

So, [tex]f(g(t))=\sqrt{9^2+(25t)^2}[/tex]

[tex]f(g(t))=\sqrt{81+(652t)^2}[/tex]

Hence, this is the required solution.

Ver imagen Muscardinus