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A girl with mass m1 and a sled with mass m2 are on the frictionless ice of a frozen lake, a distance d apart but connected by a rope of negligible mass. The girl exerts a horizontal force with magnitude F on the rope. What are the acceleration magnitudes of (a) the sled and (b) the girl? (c) How far from the girl's initial position do they meet? State your answers in terms of the given variables.

Respuesta :

Answer:

a)[tex]a_2=\dfrac{F}{m_2}[/tex]

b)[tex]a_1=\dfrac{F}{m_1}[/tex]

c)ex]x=\dfrac{m_2\times d}{m_1+m_2}[/tex]

Explanation:

Given that

Mass of girl =[tex]m_1[/tex]

Mass of sled=[tex]m_2[/tex]

Force = F

We know that from second law of Newton's

F =m a

a)

[tex]F=m_2.a_2[/tex]

[tex]a_2=\dfrac{F}{m_2}[/tex]

b)

[tex]F=m_1.a_1[/tex]

[tex]a_1=\dfrac{F}{m_1}[/tex]

c)

The distance ,x

[tex]x=\dfrac{m_1\times 0+m_2\times d}{m_1+m_2}[/tex]

[tex]x=\dfrac{m_2\times d}{m_1+m_2}[/tex]

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