Respuesta :

assuming is a circle of course

[tex]\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-5}{ h},\stackrel{-9}{ k})\qquad \qquad radius=\stackrel{6}{ r} \\\\[-0.35em] ~\dotfill\\[2em] [x-(-5)]^2+[y-(-9)]^2=6^2\implies (x+5)^2+(y+9)^2=36[/tex]