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Two people, one with mass m1 and the other with mass m2, stand on a stationary sled with mass M on a frozen lake. Assume that the ice is frictionless. a) The first person (with mass m1) jumps off the sled with a velocity −sxˆ relative to the (stationary) sled. What is his velocity? Use conservation of momentum to find the velocity of the sled (which is still carrying the second person).

Respuesta :

Answer:

[tex]V=\dfrac{m_1s}{m_2+M}[/tex]

Explanation:

As we know that if there is no any external force on the system then the linear  momentum of system will remain conserve.

Linear momentum P= m .v

If F(net) = 0 [tex]P_i=P_f[/tex]

Given that velocity of first person is s .

Form conservation of momentum

Let V is the final velocity

Initial momentum = [tex]m_1.s[/tex]

Final momentum =[tex](m_2+M)V[/tex]

[tex]m_1s=(m_2+M)V[/tex]

[tex]V=\dfrac{m_1s}{m_2+M}[/tex]

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