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The deepest trench in the world is 11,000 m in depth. Assuming sea water to have a constant density of 1050 kg/m, determine the pressure at this point in atmospheres.

Respuesta :

Answer:

113406825 N/m²

Explanation:

The pressure at depth of 11,000 m can be calculated by:

Pressure = Atmospheric pressure + Pressure  due to height

Atmospheric pressure = 101325 N/m²

Also,  

[tex]P_{height}=\rho\times g\times h[/tex]

Where,  

[tex]\rho[/tex] is the density of water ([tex]\rho=1050\ kg/m^3[/tex])

g is the gravitational acceleration = 9.81 m/s²

h = 11,000 m

[tex]P_{height}=1050\ kg/m^3\times 9.81\ m/s^2\times 11000\ m[/tex]

Pressure  due to height = 113305500 N/m²

Pressure = Atmospheric pressure + Pressure  due to height = 101325 N/m² + 113305500 N/m² = 113406825 N/m²

Answer:

113406825 N/m²

Explanation:

The pressure at depth of 11,000 m can be calculated by:

Pressure = Atmospheric pressure + Pressure  due to height

Atmospheric pressure = 101325 N/m²

Also,  

Where,  

is the density of water ()

g is the gravitational acceleration = 9.81 m/s²

h = 11,000 m

Pressure  due to height = 113305500 N/m²

Pressure = Atmospheric pressure + Pressure  due to height = 101325 N/m² + 113305500 N/m² = 113406825 N/m²

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