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Given the equation square root of 8x plus 1 = 5, solve for x and identify if it is an extraneous solution. x = one fourth, solution is not extraneous x = one fourth, solution is extraneous x = 3, solution is not extraneous x = 3, solution is extraneous

Respuesta :

calculista

Answer:

x=3, solution is not extraneous

Step-by-step explanation:

we have

[tex]\sqrt{8x+1}=5[/tex]

Solve for x

squared both sides

[tex](\sqrt{8x+1})^2=5^2[/tex]

[tex]8x+1=25\\8x=25-1\\8x=24\\x=3[/tex]

Verify

For x=3

[tex]\sqrt{8(3)+1}=5[/tex]

[tex]\sqrt{24+1}=5[/tex]

[tex]\sqrt{25}=5[/tex]

[tex]5=5[/tex] -----> is true

therefore

x=3, solution is not extraneous

406552

Answer:

X=3, the solution is not extraneous.

Step-by-step explanation:

Took quiz and got it right.

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