Answer:
The product of [tex]3_{5}^{2}[/tex] and [tex]2_{3}^{1}[/tex] is [tex]6_{19}^{1}[/tex]
Solution:
Here we have to multiply two numbers that is [tex]3_{5}^{2}[/tex] and [tex]2_{3}^{1}[/tex] which are in mixed form. We first convert them in fraction form to get the final product.
The number [tex]3_{5}^{2}[/tex] can be written in fraction form as [tex]\frac{[(5 \times 3)+2]}{5}=\frac{17}{5}[/tex]
The number [tex]2_{3}^{1}[/tex] can be written in fraction form as [tex]\frac{[3 \times 2)+1]}{3}=\frac{7}{3}[/tex]
Therefore multiplying [tex]\frac{17}{5} \times \frac{7}{3}[/tex] we get ,
[tex]\frac{17}{5} \times \frac{7}{3}=\frac{119}{15}[/tex]
When we divide 119 by 15 we get 6 as quotient and 1 as remainder.
Therefore [tex]\frac{119}{15}[/tex] can be written in mixed form as [tex]6_{19}^{1}[/tex]
