Answer:
In 2730 ways medal can be distributed
Explanation:
We have given there are total 15 athletes are running in the race
So total number = 15
We have to choose 1 gold medal winner, 1 silver medal winner and 1 bronze medal winner
Means we have to select 3 athletes from 15 athletes
So number of way of selection will be [tex]^{15}P_3[/tex]
[tex]^{15}P_3=\frac{15!}{(15-3)!}=\frac{15!}{12!}=\frac{15\times 14\times 13\times 12!}{12!}=2730[/tex]
So in 2730 ways medal can be distributed