Respuesta :
Answer: Our required probability is 0.328.
Step-by-step explanation:
Since we have given that
there is number on the lottery is from 1 to 38.
6 numbers are selected.
We need to find the probability of holding a ticket that has zero winning numbers out of the 6 numbers selected for the winning ticket.
So, it should be other than 6 numbers.
Remaining numbers = 38-6 = 32
So, our probability becomes
[tex]\dfrac{^{32}C_6}{^{38}C_6}\\\\=\dfrac{906192}{2760681}\\\\=0.328[/tex]
Hence, our required probability is 0.328.
By applying concept of combination we got that probability of holding a ticket that has zero winning numbers out of the 6 numbers selected for the winning ticket is 0.328
What is probability ?
Probability is chances of occurring of an event.
Total number = 38 { integer from 1 to 38}
Total selected number =6
Remaining numbers - 38-6=32
probability of holding a ticket that has zero winning numbers out of the 6 numbers selected for the winning ticket can be calculated as
[tex]\frac{{ }^{32} C_{6}}{{ }^{38} C_{6}}[/tex]
=0.328
By applying concept of combination we got that probability of holding a ticket that has zero winning numbers out of the 6 numbers selected for the winning ticket is 0.328
To learn more about probability visit : brainly.com/question/24756209
