You wish to prepare a tape-casting slip containing 50 vol% Al2O3 and 50 vol% polyvinyl butyral (PVB) binder. If the density of Al2O3 is 3.98 g/cm and that of PVB is 1.08 g/cm?, how many of grams of PVB are required to produce 1000 g of tape?

Respuesta :

Answer: The mass of PVB required to produce 1000 grams of tape is 213.4 grams

Explanation:

To calculate the mass of aluminium oxide, we use the equation:

[tex]\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}[/tex]       .......(1)

  • For [tex]Al_2O_3[/tex]

We are given:

50% (v/v) of [tex]Al_2O_3[/tex]

This means that 50 mL of aluminium oxide is present in 100 mL of tape

Calculating the mass of aluminium oxide by using equation 1:

Density of aluminium oxide = [tex]3.98 g/cm^3[/tex]

Volume of aluminium oxide = [tex]50mL=50cm^3[/tex]     (Conversion factor:  [tex]1mL=1cm^3[/tex] )

Putting values in equation 1, we get:

[tex]3.98g/cm^3=\frac{\text{Mass of aluminium oxide}}{50cm^3}\\\\\text{Mass of aluminium oxide}=(3.98g/cm^3\times 50cm^3)=199g[/tex]

Mass of aluminium oxide = 199 g

  • For PVB:

We are given:

50% (v/v) of PVB

This means that 50 mL of PVB is present in 100 mL of tape

Calculating the mass of PVB by using equation 1:

Density of PVB = [tex]1.08 g/cm^3[/tex]

Volume of PVB = [tex]50mL=50cm^3[/tex]

Putting values in equation 1, we get:

[tex]1.08g/cm^3=\frac{\text{Mass of PVB}}{50cm^3}\\\\\text{Mass of PVB}=(1.08g/cm^3\times 50cm^3)=54g[/tex]

Mass of PVB = 54 g

Mass of tape = Mass of aluminium oxide + mass of PVB

Mass of tape = [199 + 54] g = 253 g

To calculate the mass of PVB required to produce 1000 g of tape, we use unitary method:

When 253 grams of tape is made, the mass of PVB required is 54 g

So, when 1000 grams of tape is made, the mass of PVB required will be = [tex]\frac{54}{253}\times 1000=213.4g[/tex]

Hence, the mass of PVB required to produce 1000 grams of tape is 213.4 grams