Answer:
The concentration in the outlet water is 7.36x10-6 gNH3/gH2O
Explanation:
We need to have the same units to do the operations so that we can substract the activity of the bacteria from the flow rate of gNH3/s for this we first need to know which is the flow of gNH3/s in the water flow rate for this we:
[tex]25\frac{gH2O}{s} (\frac{9x10^{-6}gNH3 }{gH2O}) = 2.25x10^{-4}\frac{gNH3}{s}[/tex]
As you can see we used the concentration of NH3 in H2O to have the gNH3/s. Now we jst susbtract the activity of the baterias to the initial concentration of the water
[tex]2.25\frac{gNH3}{s} - 41x10^{-6}\frac{gNH3}{s} = 1.84x10^{-4}\frac{gNH3}{s}[/tex]
We can do this operation because the units are the same.
Now we just need to convert the 1.84x10-4 gNH3/s to concentration of gNH3/gH2O, for this we just neet to divide the concentration by the flow of the water (25gH2O/s)
[tex]\frac{1.84x10^{-4}\frac{gNH3}{s} }{25\frac{gH2O}{s} } = 7.36x10^{-6}\frac{gNH3}{gH2O}[/tex]
We cancel the units and when we realice the division we get that the outlet concentration of the water is 7.36x10-6gNH3/gH2O