A closed-loop ecosystem is being designed for long-duration space missions. Within that system, a biofilter will utilize bacteria to convert nitrogen from fish waste (NH3) into a form usable by plants (NO3-). The biofilter consists of a cylinder filled with spherical particles (like a jar full of marbles) upon which the bacteria attach, and water then flows through the cylinder past the bacteria. The water flow rate through the system is 25 g H20 / s, and the inlet concentration of NH3in the water is 9x10-6g NH3/ g H20. If the bacteria in the filter are removing NH3at a rate of 41x10-6(g NH3)/s, what is the concentration of NH3in the outlet water, in g NH3/ g H20?

Respuesta :

Answer:

The concentration in the outlet water is 7.36x10-6 gNH3/gH2O

Explanation:

We need to have the same units to do the operations so that we can substract the activity of the bacteria from the flow rate of gNH3/s for this we first need to know which is the flow of gNH3/s in the water flow rate for this we:

[tex]25\frac{gH2O}{s} (\frac{9x10^{-6}gNH3 }{gH2O}) = 2.25x10^{-4}\frac{gNH3}{s}[/tex]

As you can see we used the concentration of NH3 in H2O to have the gNH3/s. Now we jst susbtract the activity of the baterias to the initial concentration of the water

[tex]2.25\frac{gNH3}{s} - 41x10^{-6}\frac{gNH3}{s} = 1.84x10^{-4}\frac{gNH3}{s}[/tex]

We can do this operation because the units are the same.

Now we just need to convert the 1.84x10-4 gNH3/s to concentration of gNH3/gH2O, for this we just neet to divide the concentration by the flow of the water (25gH2O/s)

[tex]\frac{1.84x10^{-4}\frac{gNH3}{s} }{25\frac{gH2O}{s} } = 7.36x10^{-6}\frac{gNH3}{gH2O}[/tex]

We cancel the units and when we realice the division we get that the outlet concentration of the water is 7.36x10-6gNH3/gH2O