Answer:
B(x, y) = (-2, -2)
Step-by-step explanation:
Given: AB: AC (m₁: m₂) = 1 : 2, A (x₁, y₁) = (-5, 2) and B(x₂, y₂) = (4, -10)
To find: Coordinates of B (x, y)
Using section formula:
[tex]x = \frac{m_1x_2+ m_2x_1}{m_1 + m_2}\ and\ y = \frac{m_1y_2+ m_2y_1}{m_1 + m_2}[/tex]
∴ [tex]x = \frac{(1\times 4) + (2\times(-5))}{1 + 2} = \frac{4 - 10}{3} = \frac{-6}{3} = -2[/tex]
and [tex]x = \frac{(1\times (-10)) + (2\times 2)}{1 + 2} = \frac{-10 + 4}{3} = \frac{-6}{3} = -2[/tex]
Therefore Coordinates of B (x, y) is (-2, -2).