what is the equation of a line that is parallel to -3x + 4y = 4 and passes through the point (4, 0) ?

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Bladewolf463 Bladewolf463 · Answer 1 · 2019-10-11T17:50:13+02:00

Answer:

y=3x4-3

Step-by-step explanation:

find the equation of the line parallel to the line −3x+4y=4 passing through the point (4,0).

The equation of the line in the slope-intercept form is y=3x4+1.

The slope of the parallel line is the same: m=34.

So, the equation of the parallel line is y=3x4+a.

To find a, we use the fact that the line should pass through the given point: 0=(34)⋅(4)+a.

Thus, a=−3.

Therefore, the equation of the line is y=3x4−3.

Answer: y=3x4−3.

tatendagota tatendagota · Answer 2 · 2020-04-02T02:29:31+02:00

Answer:

[tex]y = \frac{3}{4}x - 1[/tex]

Step-by-step explanation:

Parallel lines have equal gradients.

Therefore, the equation -3x + 4y = 4 will be expressed as follows in the form

[tex]y = mx + c[/tex]

where m = gradient

c = y-intercept

4y = 3x + 4

[tex]y = \frac{3}{4}x + 1[/tex]

from the equation, the gradient = [tex]\frac{3}{4}[/tex]

the equation should pass through the line with point (x , y) and (4 , 0) and have the gradient of 3/4

This means that:

[tex]\frac{y}{x-4} = \frac{3}{4}[/tex]

y = [tex]\frac{3}{4}(x-4)[/tex]

[tex]y = \frac{3}{4}x -1[/tex]