Answer:
The car takes 7.2 seconds to come to a complete stop when moving aExplanation:
t 18 m/s decelerates at - 2.5 m/[tex]s^2[/tex].
From the given statements, we know
Initial Velocity (u) = 18 m/s
Final Velocity (v) = 0 m/s
Acceleration (a) = - 2.5 m/[tex]s^2[/tex]
Applying the 1st Equation of Motion
v = u + at
and substituting the values, we get
t=[tex]\frac{\mathrm{v}-\mathrm{u}}{\mathrm{a}}[/tex]
= [tex]\frac{0-18}{-2.5}[/tex] = 7.2 seconds
