emilyyroe
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Examine the statement and balanced equation.

Pure elemental iron undergoes a single replacement reaction with sulfuric acid (H2SO4) to produce iron(III) sulfate (Fe2(SO4)3) and hydrogen gas.

2Fe + 3H2SO4 → Fe2(SO4)3 + 3H2
(M Fe = 55.8 g/mol, M H2SO4 = 98.1 g/mol, M Fe2(SO4)3 = 399.9 g/mol, M H2 = 2.0 g/mol)

If 3.21 x 1012 mol of iron(III) sulfate are formed, how many g of it will be produced?

Respuesta :

joseaaronlara

Answer:

The answer to your question is:   1.28 x 10 ¹⁵ g of Fe₂(SO₄)₃

Explanation:

Single replacement reaction:

                                  2Fe   +    3H₂SO₄    →    Fe₂(SO₄)₃   +   3H₂

M Fe = 55.8 g/mol

M H₂SO₄ = 98.1 g/mol

M Fe₂(SO₄)₃ = 399.9 g/mol

M H₂ = 2.0 g/mol

Fe₂(SO₄)₃ = 3.21 x 10¹² mol

Fe₂(SO₄)₃ =  ? g

                          1 mol of Fe₂(SO₄)₃ -----------------  399.9 g/mol of Fe₂(SO₄)₃

                          3.21 x 10¹² mol Fe₂(SO₄)₃ --------    x

   

                         x = (3.21 x 10¹² x 399.9 ) / 1

                         x = 1.28 x 10 ¹⁵ g of Fe₂(SO₄)₃

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