John wishes to set up an account for his grandfather so that he can have some extra money each month. John wants his grandfather to be able to withdraw $120 per month for the next 3 years. How much must John invest today at 5% per year compounded monthly so that his grandfather can withdraw $120 per month for the next 3 years?

Respuesta :

Answer:

John must invest $3719.4

Explanation:

It is given that John grandfather withdraws $120 per month for 3 year

So total month = 12 ×3 =36 months

Total amount withdrawn S = 36×120 = 4320

m = 12 times per year

Rate of interest i = 5 % = 0.05

We know that [tex]S=P(1+\frac{i}{m})^{mt}[/tex]

[tex]4320=P(1+\frac{0.05}{12})^{36}[/tex]

[tex]4320=P\times 1.1614[/tex]

P = $3719.41

So john must invest $3719.4

The total amount of money that the john should invest is as a principal is $3,719.41.

What is compound interest?

Compound interest is the amount of interest that is paid or received on the accumulated amount of money,

Means firstly is paid or received on the principal, then it is calculated on the amount of principal with the amount of previous interest.

Computation of amount of principal:

According to the given condition,

Interest rate(r)= 5%

Fraction when compounded monthly for three years:

[tex]r=\dfrac{\frac{5}{12} }{100} \\\\r=0.0041[/tex]

Number of period(n)is 3 years means:

[tex]3\text{Years}\times\text{12 Months }= 36 \text{Months}[/tex]

Then total amount withdrawn per year is $120 for 3 years is:

[tex]3\text{Months}\times\$120 =\$4,230[/tex]

Now apply the formula of compound amount to get the invested amount is:

[tex]A=\text{P}(1+i)^n}[/tex]

Now substitute the given values in the formula:

[tex]A=\text{P}(1+i)^n}\\\\\$4,320=\text{P}(1+0.0041)^3^6}\\\\\$4,320= P(1.1614)\\\\\text{P}= \$3,719.41[/tex]

Therefore, the invested amount at the starting of the year is $3,719.41.

Learn more about compound interest, refer to:

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