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A bird watcher spots a sparrow in a tree. The sparrow sits in a nest that is 10.5 feet above the bird watcher's eye level, at a 35° angle of elevation from the bird watcher. The bird watcher then notices a hawk in the same tree, 7.4 feet above the sparrow, at a certain angle of elevation. The bird watcher stands 15 feet from the base of the tree. What is the angle of elevation from the bird watcher to the hawk?

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krlosdark12

Answer:

the angle is 50 degrees.

Explanation:

To solve this trigonometric problem we need ot remember that:

[tex]\alpha=arctg(\frac{O}{A})[/tex]

where O is the opposite side of the triangle and A the adjacent

The hawk is 7.4 feet above the sparrow so:

[tex]O=10.5+7.4\\O=17.9ft[/tex]

[tex]\alpha =arctg(\frac{17.9}{15})=50^o[/tex]

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