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Class records at Rockwood College indicate that a student selected at random has probability 0.8 of passing French 101. For the student who passes French 101, the probability is 0.76 that he or she will pass French 102. What is the probability that a student selected at random will pass both French 101 and French 102?

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Answer:

The probability that a student selected at random will pass both French 101 and French 102 is 0,608‬

Step-by-step explanation:

In this case,  we want to know the probability of two events happening , the  2 events are that the student  selected pass both French 101 and French 102

So, the probability of a student passing French 101 is 0.8

The probability of a student passing French 102 is 0.76

We are looking the probability of 2 both event occur , so we have to multiply the probability of both events.  

Probability that a student selected at random will pass both French 101 and French 102= P passing French 101* P passing French 102

P= 0.8*0.76= 0,608‬

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