Answer:480 ways
Explanation:
Given
There are 3-Volume series i.e.
[tex]V_1,V_2,V_3[/tex]
No of ways in which they can be arranged in order is 2 i.e. [tex]V_1,V_2,V_3[/tex] or [tex]V_3,V_2,V_1[/tex]
For 2 volume series
There are two ways in which 2 volume series is arranged
[tex]V_1,V_2 or V_2,V_1[/tex]
Considering 3 volume books to be a single book denoted by a
and 2 volume books to be a single denoted by b
Thus we have to arrange a,b and 3 others books
No of ways in which 5 books can be arranged is 5!
also a and b can be arranged in two ways internally so
there are total of =[tex]5!\times 2\times 2[/tex]=480 ways
