Respuesta :
Answer:
The ratio of asteroid-A’s acceleration to asteroid-B’s acceleration is 37:7800.
Explanation:
Mass of asteroid-A = m =[tex]7.80\times 10^{20} kg[/tex]
Mass of asteroid-B = m' = [tex]3.70\times 10^{18} kg[/tex]
As we know , Force = mass × Acceleration
1) Force on an asteroid-A
[tex]F = m\times a[/tex]
where , a is the acceleration due to force applied on asteroid-A
2) Force on an asteroid-B
[tex]F' = m'\times a'[/tex]
where , a' is the acceleration due to the force applied on asteroid-B
Same force is exerted on the both the asteroids say F.
F = F'
[tex]m\times a=m'\times a'[/tex]
[tex]\frac{a}{a'}=\frac{3.70\times 10^{18} kg}{7.80\times 10^{20} kg}=\frac{37}{7800}[/tex]
The ratio of asteroid-A’s acceleration to asteroid-B’s acceleration is 37:7800.
