Answer:
VB − VA = g tAB & (VA + VB)/2 = h / tAB
Explanation:
s = h = Displacement
tAB = t = Time taken
VA = u = Initial velocity
VB = v = Final velocity
a = g = Acceleration due to gravity = 9.8 m/s²
[tex]s=ut+\frac{1}{2}at^2\\\Rightarrow u=\frac{s-\frac{1}{2}at^2}{t}\\\Rightarrow u=\frac{3.8-\frac{1}{2}\times 9.8\times 0.02^2}{0.02}\\\Rightarrow u=189.902\ m/s[/tex]
[tex]v=u+at\\\Rightarrow v=189.902+9.8\times 0.02\\\Rightarrow v=190.098\ m/s[/tex]
[tex]\frac{v+u}{2}=\frac{190.098+189.902}{2}=190\ s[/tex]
[tex]\frac{h}{t}=\frac{3.8}{0.02}=190\ s[/tex]
Hence, the equations VB − VA = g tAB & (VA + VB)/2 = h / tAB will be used
