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The manager of a concert venue is adding up the proceeds from a Friday night show. Tickets sold for $8, $10, and $12 depending on where the seats were. Twice as many $8 seats were sold as $10, and 10 more $12 seats were sold than $10. The total proceeds were $3,122. How many of each type of ticket were sold?

Respuesta :

Answer:

Total number $10 ticket = 79

Total number of $8 ticket = 2x = 2×79 = 158

Total number of $12 ticket = x+10 = 79+10 =89  

Explanation:

We have given that there are three tickets available of Rs $8 , $10 and $12

Let x $10 tickets are sold

Then according to question

Number of $8 ticket sold = 2x

And number of $12 tickets sold = x+10

We have given total proceeds = $3122

So [tex]10x+(8\times 2x)+12\times (x+10)=3122[/tex]

[tex]10x+16x+12x+120=3122[/tex]

[tex]38x=3002[/tex]

x = 79

So total number $10 ticket = 79

Total number of $8 ticket = 2x = 2×79 = 158

Total number of $12 ticket = x+10 = 79+10 =89  

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